How to calculate "mass of any Planet"?

Do you know how to measure mass of any planet? How it possible? There are the many type of questions like this?

 That is a very interesting topic for all of us. Everybody know Earth is the third planet from the Sun. The mass of the Earth may be determined using Newton's law of gravitation. It is given as the force (F), which is equal to the Gravitational constant multiplied by the mass of the planet and the mass of the object, divided by the square of the radius of the planet. We set this equal to the fundamental equation, force (F) equals mass (m) multiplied by acceleration (a). We know that the acceleration due to gravity is equal to 9.8 m/s2, the Gravitational constant (G) is 6.673 × 10−11 Nm2/kg2, the radius of the Earth is 6.37 × 106 m, and mass cancels out. When we rearrange the equation and plug all the numbers in, we find that the mass of the Earth is 5.96 × 1024 kg.

F = Gm1m2/r2 = ma

Gm/r2 = g

m = gr2/G

m = (9.8 m/s2)

(6.37 × 106 m)2/(6.673 × 10−11 Nm2/kg2)

m = 5.96 × 1024 kg

And did you know

Our Earth gains mass each day, as a result of incoming debris from space. This occurs in the forms of "falling stars", or meteors, on a dark night. The actual amount of added material depends on each study, though it is estimated that 10 to the 8th power kilograms of in-falling matter accumulates every day.

In the past we were great scientist "Sir Isaac Newton" greatly contributed to the study of physics and therefore, his efforts determined the mass of the Earth. His law of gravity and second law of motion are used together to obtain a value for the mass of our planet. Newton's law of gravity formulates the gravitational force that two masses exert on each other and is given by

F = GmM/r2

M an m are the two masses, r is the separation between them, and G is the universal gravitational constant which was calculated by Henry Cavendish in 1798, which has a value of 6.67 × 10−11 m3/(kg sec2).

If we assumed that M is the mass of the Earth, and m is the mass of an object on the surface of the Earth, we can solve for M by equating Newton's Law of Gravity with his second law of motion

F = ma

We have:

F = GmM/r2 = ma → GM/r2 = a

Solving for M, the mass of the Earth, and using

Where

a = 9.8 m/s2,
r = 6.38 × 106 m, and
G = 6.67 × 10−11 m3/(kg sec2)

we obtain:

M = ar2/G = 5.98 × 1024 kg.